In the circuit shown, the capacitor C 1 and C 2 have capacitance each. The switch S is closed at time t = 0. Taking Q 0 = CE and τ = RC, the charge on C 2 after time t will be -
A
Q 0 (1 – 
)
)
B
Q 0 (1 – 
)
)
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
Q = Q 0 (1 – 
)
= Q 0 (1 – 
)
= Q 0 (1 – 
)
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